JUGGERNAUT Posted September 8, 2003 Share Posted September 8, 2003 If we look solely at the gamelog which is the simplest measure to use: http://baseball.espn.go.com/mlb/boxscore?g...ameId=230907104 Batting HR: F Thomas (39, 7th inning off D Baez 2 on, 2 Out); P Konerko (18, 8th inning off D Lee 1 on, 1 Out) RBI: M Ordonez (85), C Lee (98), F Thomas 3 (93), P Konerko 2 (65) S: R Alomar, S Alomar Jr SF: C Lee 2-out RBI: F Thomas Runners left in scoring position, 2 out- R Alomar 1, P Konerko 1, M Ordonez 1 Team LOB: 7 Baserunning CS: M Ordonez (5, 2nd base by C Lee/V Martinez) Can we determine a PTC from this? + Pts: HR: (2*HR) Thomas = 2 Koney = 2 RBI:(1*RBI) Thomas = 3 Koney = 2 Maggs = 1 Lee = 1 2-out RBI: (1*RBI) Thomas = 1 - Pts: all -1 PT RON,2 outs: Koney = -1 CS: Maggs = -1 Thomas should win the hitters PTC 6-3 over Koney. If the SOX get shut out, then you can look at H, & AB. But otherwise, it should be the players driving in runs that get the most weight. Similarly on the PITCHING side: IP H R ER BB SO HR PC-ST ERA D Wright 5 5 2 2 1 4 2 75-47 5.42 K Wunsch 1 0 0 0 0 1 0 8-6 1.74 S Sullivan 1/3 1 1 1 1 0 0 15-7 6.35 S Schow 2/3 0 0 0 1 1 0 13-4 4.85 D Marte 1 1 0 0 0 3 0 17-10 1.66 T Gordon 1 0 0 0 0 2 0 8-7 3.33 I like ST/(R+1) as the winning PTC measure: (ST = strikes, R = runs scored) Wright = 16 Wunsch = 6 Sullivan = 3.5 Schow = 4 Marte = 10 Gordon = 7 After all hits are only counted as strikes. Now if you want only 1 PTC then for a Pitcher to win he must have a score > 3*(highest hitter) Thomas wins the PTC 18-16 over Wright. Proof: Wright needed just 10 more ST's to win. That would have left him with 6ip, 2r, 57ST's I think that was worthy of the win. Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.